[SOLVED] Why does ftell skips some positions in the file?

Why does ftell skips some positions in the file?

I have a text file named myfile.txt which reads:

line 1
l

My code:

#include<stdio.h>
int main(){
    FILE *f = fopen("myfile.txt","r");
    if(f==NULL){
        FILE *fp=fopen("myfile.txt","w");
        fclose(fp);
        f = fopen("myfile.txt","r");
    }
    while(!feof(f)){
        printf("\ncharacter number %d    ",ftell(f));
        putchar(fgetc(f));      
    }
    fclose(f);
    return 0;
}

The output is :

character number 0    l
character number 1    i
character number 2    n
character number 3    e
character number 4
character number 5    1
character number 6

character number 8    l
character number 9

Whenever a \n is encountered, the ftell skips one value for example it has skipped the value 7. Why is it so? Please explain me in detail, I want to know.

Solution

The problem lies in the newline character, which in Windows is \r\n (Does Windows carriage return \r\n consist of two characters or one character?).

Try changing these:

fopen("myfile.txt","r");

to these:

fopen("myfile.txt","rb");

where b is for binary mode.

Binary mode makes a difference on Windows where text mode maps the two character carriage return, line feed sequence to a single new-line character. Note: No mapping is needed on Linux.