I am trying to determine the width of a column in inches. This formula sets the width to 5 inches but I cannot see how wide in inches column C is...
Columns("D:D").ColumnWidth = Application.InchesToPoints(5) * (Columns("D:D").ColumnWidth / Columns("D:D").Width)
Divide the column width by Application.InchesToPoints(1) (which is basically 72).
MsgBox Columns("C").Width / Application.InchesToPoints(1)
"Columnwidth" isn't in point, "Width" is in points.