at this moment I'm stucked on my code.
I want to display the names of accepted friends.
I have two tables:
Users
[id, useruniqueid, username]
Friends
[id, user_a, user_b, status]
(status can be requested, pending or accepted)
For example:
Users:
1, 123, Kaan2106
2, 321, SOUser1
3, 456, SOU2
4, 654, Some4
Friends:
1, 123, 321, accepted
2, 321, 123, accepted
3, 456, 123, accepted
4, 123, 456, accepted
5, 654, 123, pending
6, 123, 654, requested
I want to display my friend(s) names like: "SOUser1" (because it's accepted)
And this is what I done:
<table>
<tr>
<td>Name</td>
</tr>
<?php
$getem = mysql_query("SELECT * FROM Friends WHERE (`status` = 'accepted') AND (`user_a` = '$UserUUID' OR `user_b` = '$UserUUID') LIMIT 10");
while($row = mysql_fetch_assoc($getem)) {
$friendsql = mysql_query("SELECT * FROM Users WHERE useruniqueid = '" . ($row['user_a'] == $UserUUID ? $row['user_b'] : $row['user_a']) . "'");
$friendrow = mysql_fetch_assoc($friendsql);
?>
<tr>
<td class="friend-name">
<?php echo $friendrow['username']; ?>
</td>
</tr>
<?php } ?>
</table>
And my output is like this SOUser1, SOUser1, SOU2, SOU2
(unwanted doubles)
The expected output should be like this SOUser1, SOU2
(no doubles)
I know that mysql_* is deprecated
If you do it all in one query (with a join
), you can use MySQL's distinct
operator to only return one instance of each user's name.
Try using a query like the one below. The join uses a case statement so that it joins the Friends table by either user_a or user_b, depending on which one is not the $UserUUID
.
select distinct
u.username
from
Friends f
join Users u
on (
u.useruniqueid = case
when f.user_a='{$UserUUID}' then f.user_b
else f.user_a
end
)
where
(f.user_a = '{$UserUUID}' or f.user_b = '{$UserUUID}')
and f.status='accepted'
See it in an SQL Fiddle, with $UserUUID
being set to '123'.