As stated in Effects of Type Erasure and Bridge Methods a bridge method implies that it is also a synthetic method. The question is, is it possible that invocation of isSynthetic
method returns true but isBridge
method returns false for a Method
object, i.e., if a method is synthetic does it imply that it is also a bridge method?
It's not exactly the same but the source code for isSynthetic
and isBridge
methods looks like below:
static final int SYNTHETIC = 0x00001000;
public boolean isSynthetic() {
return (getModifiers() & SYNTHETIC) != 0;
}
static final int BRIDGE = 0x00000040;
public boolean isBridge() {
return (getModifiers() & BRIDGE) != 0;
}
Why isBridge
method body is not like return isSynthetic();
?
If you are simply looking for an example of such:
Function<String, Integer> func = s -> s.length();
Arrays.stream(DeleteMe.class.getDeclaredMethods())
.peek(m -> System.out.println(m.getName() + " isSynth : " + m.isSynthetic() + " isBridge : " + m.isBridge()))
.forEach(System.out::println);
There will be entries like:
lambda$0 isSynth : true isBridge : false
lambda$1 isSynth : true isBridge : false