rregexgsubfn

Why isn't \\b in gsubfn in R working for me?

I have a string like this:

vect <- c("Thin lines are not great, I am in !!! AND You shouldn't be late OR you loose")

I want to replace, "in" to %in%", "AND" to "&", "OR" to "|".

I know this can be done using gsub like below:

gsub("\\bin\\b","%in%", vect),

but I need three different lines for each of the replacement, hence I choose to use gsubfn.

so I tried,

gsubfn("\\bin\\b|\\bAND\\b|\\bOR\\b", list("in"="%in%", "AND"= "&", "OR"="|"), vect)

but It returns a string with nothing changed, for some reason \\b is not working for the string. However, \\b does work great with gsub and I am able to replace all the three strings in by piping together using gsub.

My question is, why \\b is not working inside gsubfn. what I am missing inside my regex?

Please help.

Output should be:

"Thin lines are not great, I am %in% !!! & You shouldn't be late | you loose"

This works:

gsubfn("\\w+", list("in"="%in%", "AND"= "&", "OR"="|"), vect)
Solution

  • By default, Tcl regex engine is used, see gsubfn docs:

    If the R installation has tcltk capability then the tcl engine is used unless FUN is a proto object or perl=TRUE in which case the "R" engine is used (regardless of the setting of this argument).

    So, word boundaries are defined with \y:

    > gsubfn("\\y(in|AND|OR)\\y", list("in"="%in%", "AND"= "&", "OR"="|"), vect)
[1] "Thin lines are not great, I am %in% !!! & You shouldn't be late | you loose"

    Ainother way is by using \m as leading word boundary and \M for a trailing word boundary:

    > gsubfn("\\m(in|AND|OR)\\M", list("in"="%in%", "AND"= "&", "OR"="|"), vect)
[1] "Thin lines are not great, I am %in% !!! & You shouldn't be late | you loose"

    You may pass perl=TRUE and use \b:

    > gsubfn("\\b(in|AND|OR)\\b", list("in"="%in%", "AND"= "&", "OR"="|"), vect, perl=TRUE)
[1] "Thin lines are not great, I am %in% !!! & You shouldn't be late | you loose"