I have two lists
available_points = [[2,3], [4,5], [1,2], [6,8], [5,9], [51,35]]
and
solution = [[3,5], [2,1]]
I'm trying to pop a point in available_points
and append it to solution
for which the sum of euclidean distances from that point, to all points in the solution
is the greatest.
So, I would get this
solution = [[3,5], [2,1], [51,35]]
I was able to select the initial 2 furthest points like this, but not sure how to proceed.
import numpy as np
from scipy.spatial.distance import pdist, squareform
available_points = np.array([[2,3], [4,5], [1,2], [6,8], [5,9], [51,35]])
D = squareform(pdist(available_points)
I_row, I_col = np.unravel_index(np.argmax(D), D.shape)
solution = available_points[[I_row, I_col]]
which gives me
solution = array([[1, 2], [51, 35]])
You can use cdist
-
In [1]: from scipy.spatial.distance import cdist
In [2]: max_pt=available_points[cdist(available_points, solution).sum(1).argmax()]
In [3]: np.vstack((solution, max_pt))
Out[3]:
array([[ 3, 5],
[ 2, 1],
[51, 35]])