Treat an emoji as one character in a regex

Here's a small example:

reg = ur"((?P<initial>[+\-👍])(?P<rest>.+?))$"

(In both cases the file has -*- coding: utf-8 -*-)

In Python 2:

re.match(reg, u"👍hello").groupdict()
# => {u'initial': u'\ud83d', u'rest': u'\udc4dhello'}
# unicode why must you do this

Whereas, in Python 3:

re.match(reg, "👍hello").groupdict()
# => {'initial': '👍', 'rest': 'hello'}

The above behaviour is 100% perfect, but switching to Python 3 is currently not an option. What's the best way to replicate 3's results in 2, that works in both narrow and wide Python builds? The 👍 appears to be coming to me in the format "\ud83d\udc4d", which is what's making this tricky.

In a Python 2 narrow build, non-BMP characters are two surrogate code points, so you can't use them in the [] syntax correctly. u'[👍] is equivalent to u'[\ud83d\udc4d]', which means "match one of \ud83d or \udc4d. Python 2.7 example:

>>> u'\U0001f44d' == u'\ud83d\udc4d' == u'👍'
True
>>> re.findall(u'[👍]',u'👍')
[u'\ud83d', u'\udc4d']

To fix in both Python 2 and 3, match u'👍 OR [+-]. This returns the correct result in both Python 2 and 3:

#coding:utf8
from __future__ import print_function
import re

# Note the 'ur' syntax is an error in Python 3, so properly
# escape backslashes in the regex if needed.  In this case,
# the backslash was unnecessary.
reg = u"((?P<initial>👍|[+-])(?P<rest>.+?))$"

tests = u'👍hello',u'-hello',u'+hello',u'\\hello'
for test in tests:
    m = re.match(reg,test)
    if m:
        print(test,m.groups())
    else:
        print(test,m)

Output (Python 2.7):

👍hello (u'\U0001f44dhello', u'\U0001f44d', u'hello')
-hello (u'-hello', u'-', u'hello')
+hello (u'+hello', u'+', u'hello')
\hello None

Output (Python 3.6):

👍hello ('👍hello', '👍', 'hello')
-hello ('-hello', '-', 'hello')
+hello ('+hello', '+', 'hello')
\hello None