How to use browsermob with python-selenium?

I want to use browsermob to monitor the network connections when doing a GUI test with selenium. I have found some information and documentation here and here and here, but its absolutely unclear how to really use it.

In the documentation it reads:

server = Server("path/to/browsermob-proxy")

But what is that path? Where to find it?

Also I see

java -jar browsermob.jar --port 9090

but no explanation at all as to what this jar file is, if it is part of the browsermob installation, or something unrelated.

I would appreciate if someone can provide a COMPLETE and WORKING example on how to use browsermob, and what ALL I need to install...

You can try the code below:

    from browsermobproxy import Server
    import psutil
    import time
    
    for proc in psutil.process_iter():
        # check whether the process name matches
        if proc.name() == "browsermob-proxy":
            proc.kill()
    
    dict = {'port': 8090}
    server = Server(path="./BrowserMobProxy/bin/browsermob-proxy", options=dict)
    server.start()
    time.sleep(1)
    proxy = server.create_proxy()
    time.sleep(1)
    from selenium import webdriver
    profile = webdriver.FirefoxProfile()
    selenium_proxy = proxy.selenium_proxy()
    profile.set_proxy(selenium_proxy)
    driver = webdriver.Firefox(firefox_profile=profile)
    
    
    proxy.new_har("google")
    driver.get("http://www.google.co.uk")
    print (proxy.har) # returns a HAR JSON blob
    
    server.stop()
    driver.quit()

Two things, if your code fails the process could be left open sometimes. So I added the code below for closing the duplicate instances.

import psutil
import time

for proc in psutil.process_iter():
    # check whether the process name matches
    if proc.name() == "browsermob-proxy":
        proc.kill()

Also a sleep of 1 second before and after creating the proxy.

server.start()
time.sleep(1)
proxy = server.create_proxy()
time.sleep(1)

This helps in getting rid of some intermittent issues which can be faced due to the server taking some time to start.