c++c++11copymove-semantics

Most concise way to disable copy and move semantics

The following surely works but is very tedious:

T(const T&) = delete;
T(T&&) = delete;
T& operator=(const T&) = delete;
T& operator=(T&&) = delete;

I'm trying to discover the most concise way. Will the following work?

T& operator=(T) = delete;

Update

Note that I choose T& operator=(T) instead of T& operator=(const T&) or T& operator=(T&&), because it can serve both purposes.

Solution

  • It's enough to delete the copy operations, then the move operations will get removed automatically.

    But if you're asking for "concise", according to this chart (by Howard Hinnant):

    meow

    The most concise way is to =delete move assignment operator (or move constructor, but it can cause problems mentioned in comments).

    Though, as I said above, I wouldn't use this in practice, and would instead delete the copy constructor and copy assignment.