I am using Spark 1.6, as per the official doc it is allowed to save a RDD to sequence file format, however I notice for my RDD textFile:
scala> textFile.saveAsSequenceFile("products_sequence")
<console>:30: error: value saveAsSequenceFile is not a member of org.apache.spark.rdd.RDD[String]
I googled and found similar discussions seem to suggest this works in pyspark. Is my understanding to the official doc wrong? Can saveAsSequenceFile()
be used in Scala?
The saveAsSequenceFile is only available when you have key value pairs in the RDD. The reason for this is that it is defined in PairRDDFunctions
https://spark.apache.org/docs/2.1.1/api/scala/index.html#org.apache.spark.rdd.PairRDDFunctions
You can see that the API definition takes a K and a V.
if you change your code above to
import org.apache.spark.SparkContext
import org.apache.spark.SparkConf
import org.apache.spark.rdd._
object SequeneFile extends App {
val conf = new SparkConf().setAppName("sequenceFile").setMaster("local[1]")
val sc = new SparkContext(conf)
val rdd : RDD[(String, String)] = sc.parallelize(List(("foo", "foo1"), ("bar", "bar1"), ("baz", "baz1")))
rdd.saveAsSequenceFile("foo.seq")
sc.stop()
}
This works perfectly and you will get foo.seq file. The reason why the above works is because we have an RDD which is a key value pair and not just a RDD[String].