Verilog, Parallel in Series out Shift Register

I am learning and practicing Verilog HDL. I wanted to design a 16 bit parallel in series out shift register.

module verilog_shift_register_test_PISO( din, clk, load, dout );

output reg dout ;

input [15:0] din ;
input clk ;
input load ;

reg [15:0]temp;

always @ (clk or load) begin
 if (load)
  temp <= din;
 else begin
  dout <= temp[0];
  temp <= {1'b0, temp[15:1]};
 end
end
endmodule  

I wrote this code and tried to simulate it.

simulation result

simulation_result I could not understand the reason why data output (dout) signal is always LOW

It works for me.

BUT!
That code can no be turned into gates. You must use 'posedge clk' or 'negedge clk'. Also your load is a-synchronous which is very unusual and can give race conditions against the clock edge.

always @ (posedge clk)
begin
   if (load)
      temp <= din;
   else
   begin
     dout <= temp[0];
     temp <= {1'b0, temp[15:1]};
   end
end

Furthermore it is usual to have a reset condition. As long as there is no 'load' signal the dout will produce X-es. This can very much upset the rest of your circuit. Also you have an extra clock delay in dout. You could, if you want, save a clock cycle there. Here its is with an a-synchronous active low reset:

always @ (posedge clk or negedge reset_n)
begin
   if (!reset_n)
      temp <= 16'h0000;
   else
   if (load)
      temp <= din;
   else
     temp <= {1'b0, temp[15:1]};
end

assign dout = temp[0];