I have the following path:
f_file = /home/reads_dataset_1/E2_ER/E2_ER_exp1_L1.fastq.gz
And I'd like to get only the base file name without the 2 extensions (that is, without .fastq.gz
):
E2_ER_exp1_L1
Tried:
sample_name = os.path.splitext(f_file)[0]
But I got the whole name of the path without the last extension.
may be funny and dirty, but works :)
sample_name = os.path.splitext(os.path.splitext(os.path.basename(f_file))[0])[0]
also can use shorter, nicer version:
sample_name = os.path.basename(f_file).split('.')[0]