sedsolarissolaris-10

Match and replace block using regex with sed on Solaris

This is working on some tools as regex101.com but I cannot make it work with sed.

Blocks: 

dn: abcd1,ou=test
aaaaa
bbbb
1111

dn: abcd2,ou=test
33333
ddddd
aaaaa

dn: qwert,ou=test
55555
hhhh
dddd

I want to match and replace with nothing every block that starts with dn: abcd. A block always ends with \n\n.

Regexp: (?s)\b(?:(?!\n\n).)*?\bdn: abcd\b(?:(?!\n\n).)*

Is it possible to achieve with sed?

Solution

  • is a better choice for this task.

    $ perl -00ne 'print if not /^dn: abcd/' file

    or

    $ perl -ne 'print if not /^dn: abc/ .. /^$/' file


    dn: qwert,ou=test
55555
hhhh
dddd