I have a table with 3 columns, I want to query that table such that the result will be a JSON object.
Sample data looks like this:
CREATE TABLE #Test (ValueV INT, KEYS NVARCHAR (100), ID INT)
INSERT INTO #Test
VALUES (1, N'ChangeAdress 19 - 21', 200),
(1, N'ChangeAdress 20 - 22', 200),
(1, N'ChangeAdress 22 - 24', 300),
(1, N'ChangeAdress 23 - 25', 300),
(2, N'ChangeAdress 24 - 26', 400),
(2, N'ChangeAdress 25 - 27', 400),
(3, N'ChangeAdress 26 - 28', 400),
(3, N'ChangeAdress 27 - 29', 400)
SELECT * FROM #Test
My query attempt:
SELECT ID, Keys, ValueV
FROM #Test
GROUP BY ID, keys, ValueV
FOR JSON AUTO
But that returns 1 JSON 'row'. What I want, is one row per group. Group being here ID, Value combination. I have little experience with JSON objects (which is probably visible from this query), so help would be appreciated.
The desired output (but then as JSON per row):
--------------------------------------------------
|200, 1, ChangeAdress 19 - 21, ChangeAdress 20 - 22|
|300, 1, ChangeAdress 22 - 24, ChangeAdress 23 - 25|
|400, 2, ChangeAdress 24 - 26, ChangeAdress 25 - 27|
|400, 3, ChangeAdress 26 - 28, ChangeAdress 27 - 29|
Thanks in advance!
This works (in SQL Server 2017, where STRING_AGG
is available), but is quite clumsy. I'm not sure there's not a more elegant way.
SELECT (
SELECT
ID,
ValueV,
Keys = JSON_QUERY('["' + STRING_AGG(STRING_ESCAPE(Keys, 'json'), '","') + '"]')
FOR JSON PATH
)
FROM #Test
GROUP BY ID, ValueV
For SQL Server 2016 (which has no STRING_AGG
, or STRING_ESCAPE
for that matter):
SELECT (
SELECT ID, ValueV, Keys = JSON_QUERY(REPLACE(REPLACE(
(
SELECT Keys
FROM #Test t2 WHERE t2.ID = t1.ID AND t2.ValueV = t1.ValueV
FOR JSON PATH
),
'{"Keys":', ''),
'}', ''))
FOR JSON PATH
)
FROM #Test t1
GROUP BY ID, ValueV
Even less elegant, but you take what you can get. At least we're not concatenating with FOR XML
...