Since I am noob in C++, and Udacity Quiz narrates:
The following program produces wrong out put. To fix the program, you need to change at least two of the variable types: the answer, and one of the divisors.
#include <iostream>
int main(void)
{
int numerator = 4; // no need to change type
float denominator = 5.0; // changed to float
float answer = 0.0; // changed to float
answer = numerator / denominator;
std::cout<<"answer = "<<answer; // answer = 0.8
return 0;
}
Question:How type casting implies here and Why change variable types on both sides of equality.
why not change only answer. as directed I tried setting float to answer and denominator only. and now it works, but I want to learn implicit typecasting in c++.
PS: The code is a quiz by Udacity classroom
If the both operands of the expression
numerator / denominator
have integer types then the result of the expression is also has the common integer.
To make the result of a floating type one of the operands has to be of a floating type.
On the other hand if the variable result has an integer type then there can be a truncation of the floating type expression
numerator / denominator