network-programmingipip-addressip-fragmentation

IP Fragmentation confusing

Basically I'm new to networking and I was trying work an example on fragmentation. Here is the question

Illustrate fragmentation in the form of a table given the following detail: Size of data = 24000 bits, offset = 370, M=1, D = 0 and the New MTU is 1500 bytes.

Here is my answer, DF= Do not fragment and MF = More Fragment, 24000 bits = 3000 bytes.

Id | Data Length| Data| DF | MF| Offset|
________________________________________
x  | 1500       | 1480| 0  | 1 | 370   |
----------------------------------------
x  | 1500       | 1480| 0  | 1 | 577   |
----------------------------------------
x  |   40       |   20| 1  | 0 | 744   |
________________________________________

I was wondering if this answer was good precisely for the offset column. Can Someone help?

Solution

  • It seems good, so here is the solution

    1. If total Data equals to 2980, answer is good.
    2. If you are dividing the data by 8 and then increment by this factor, answer is good.