pythonpython-3.xdictionary

How to know if a value is inside a nested dictionary

I'm new to Python and I'm still learning how to use. I have the follow dictionary:

dic = {'0': {'text': 'a', 'lang': 'es', 'rating': '4'}, '1': {'text': 'b', 'lang': 'es', 'rating': '3'}, '2': {'text': 'c', 'lang': 'es', 'rating': '1'}, '3': {'text': 'd', 'lang': 'es', 'rating': '2'}, '4': {'text': 'e', 'lang': 'es', 'rating': '5'}}

Now, I'm trying to know if the text, for example, 'a' is a value of any of those nested dictionaries (I know there is a value() function which returns the values of the dictionaries, but in this case it will only return the values of the first dictionary, won't it? Like 0,1,2,3,4)

I tried

for i in range(len(dic)):
  if text in dic[i].values():
    print("Yes")
  else:
    print("No")

But this gives me a KeyError with value '0'. I have searched for similar questions, but haven't found any which I can use to solve my problem. Can you please help me? Thanks in advance.

Solution

  • You can use any:

    dic = {'0': {'text': 'a', 'lang': 'es', 'rating': '4'}, '1': {'text': 'b', 'lang': 'es', 'rating': '3'}, '2': {'text': 'c', 'lang': 'es', 'rating': '1'}, '3': {'text': 'd', 'lang': 'es', 'rating': '2'}, '4': {'text': 'e', 'lang': 'es', 'rating': '5'}}
result = any('a' in d.values() for d in dic.values())