How to generate new own list in an internal table?

List in the internal table at the beginning:

code | name | sum
 22  | Jon  | 234.3
 22  | Jon  | 34.2
 22  | Jon  | 0
 22  | Jon  | 0
 12  | Bob  | 999.4
 12  | Bob  | 0
 45  | Anna | 0
 45  | Anna | 0
 11  | Mike | 0
 11  | Mike | 234.3

To get the output of such a list from the internal table:

code | name | sum
 22  | Jon  | 234.3
 22  | Jon  | 34.2
 12  | Bob  | 999.4
 45  | Anna | 0
 11  | Mike | 234.3

Conditions for the formation of a new (outgoing) list:

1. If the column name with several identical names (for example with four - Jon) has a value (column sum) 34.5 ... and 0, then throw away all 0 and print only non-zero.
2. If the column name with several identical names (for example two - Anna) has a value (column sum) 0 - then print only one name with the value 0.
3. The list can not be sorted - the output must have a list with the same order as the input.

I'm considering lt_grp1 will contains beginning internal table records. And i've declared lt_grp2 of same structure as lt_grp1.

  DATA: lv_index TYPE i VALUE 0.

  APPEND LINES OF lt_grp1 TO lt_grp2.
  DELETE ADJACENT DUPLICATES FROM lt_grp2 COMPARING code name.

  LOOP AT lt_grp2 INTO ls_grp1.

    LOOP AT lt_grp1 INTO ls_grp2
          WHERE code = ls_grp1-code
            AND name = ls_grp1-name.
      lv_index = lv_index + 1.
      IF ls_grp2-sum = 0.
        IF lv_index > 1.
          DELETE lt_grp1 INDEX sy-tabix.
        ENDIF.
      ELSE.
        IF lv_index > 1.
          DELETE lt_grp1 WHERE sum = 0
                          AND code = ls_grp1-code.
        ENDIF.
      ENDIF.
      CLEAR: ls_grp2.
    ENDLOOP.
    CLEAR : lv_index.
  ENDLOOP.


  CLEAR :ls_grp1.
  LOOP AT lt_grp1 INTO ls_grp1.
    WRITE: / ls_grp1-code, ls_grp1-name, ls_grp1-sum.
  ENDLOOP.

Hope this helps!

For those who think i didn't tested it.

Here is input table -

Output -