I am trying to learn prolog and i came across the following problem:
Given -
try(X):-not(not((member(X,[a,b,c])))),write(X).
I would expect the query ?- try(X)., for the following query to be something like
X=a
a;
X=b
b;
X=c
c.
But in fact, the output is:
?- try(X).
_12010
true.
Why is that? Why the variable is not initiated to some value?
In addition to what @VictoriaRuiz says, notice a few other things:
?- \+ member(X, [a,b,c]).
false.
This is false because member(X, [a,b,c]) has solutions, but the variable binding is lost when you negate it. So that means
?- \+ \+ member(X, [a,b,c]).
true.
is the same as
?- \+ false.
true.
In other words, there's nowhere for X to materialize from. Your write(X) happens outside the scope of the variable binding for X, it's as though you did this:
?- \+ false, write(X).
_4082
true.
which is basically the same as
?- write(X).
_4014
true.
If you wanted to see evidence of backtracking in the negation, you might expect to see it with this query:
?- \+ \+ (member(X, [a,b,c]), write(X), nl).
a
true.
But because you obtained a true solution on the first try, the negation of that is false. Then the negation of that is true. So we see that it produced a solution inside the goal (member(X, [a,b,c]), write(X), nl), which is enough to know that the negation of that is false. Negating false again gives you true, but no variable bindings.