I try to sort array data alphabetically but I think something is not OK.
var items;
// it's OK
items = ['a', 'á'];
items.sort((a, b) => a.localeCompare(b, 'hu'));
console.log(items); // ["a", "á"]
// it's OK, too
items = ['an', 'án'];
items.sort((a, b) => a.localeCompare(b, 'hu'));
console.log(items); // ["an", "án"]
// hmmm, it's not
items = ['an', 'ál'];
items.sort((a, b) => a.localeCompare(b, 'hu'));
console.log(items); // ["ál", "an"]The Hungarian alphabet starts with a, á, b, c...
Any suggestion, how should I use localecompare function.
In case there is no way to do it with localeCompare it seems as if you have to write your own sorter:
const alphabet = "aábcdefghijklmnopqrstuvwxyz";
function alphabetically(a, b) {
a = a.toLowerCase(), b = b.toLowerCase();
// Find the first position were the strings do not match
let position = 0;
while(a[position] === b[position]) {
// If both are the same don't swap
if(!a[position] && !b[position]) return 0;
// Otherwise the shorter one goes first
if(!a[position]) return 1;
if(!b[position]) return -1;
position++;
}
// Then sort by the characters position
return alphabet.indexOf(a[position]) - alphabet.indexOf(b[position]);
}
Usable as
array.sort(alphabetically);