When two clients join a chatroom, I want to send each of them a unique message. The first client is getting the message, but the second client is not. This is the code:
io.on('connection', (socket) => {
var roomName
var firstPlayer
var secondPlayer
var connectedClients
socket.on('roomName', (obj) => {
roomName = obj.name
socket.join(roomName)
connectedClients = Object.keys(io.sockets.adapter.rooms[roomName].sockets)
if( connectedClients.length > 1 ){
firstPlayer = connectedClients[0]
secondPlayer = connectedClients[1]
// sending the icon decision
socket.to(firstPlayer).emit( 'iconDecide', { iAmX: true } )
socket.to(secondPlayer).emit( 'iconDecide', { iAmX: false } )
}
})
socket.on('move', (obj) => {
socket.to(roomName).emit('receiveMove', obj)
}) })
How do I debug this? Is there any way I can see an error if socket.io is not able to send the message?
There is a warning in API doc indicating why it does not work:
// sending to individual socketid (private message)
io.to(`${socketId}`).emit('hey', 'I just met you');
// WARNING: `socket.to(socket.id).emit()` will NOT work, as it will send to
everyone in the room
// named `socket.id` but the sender. Please use the classic `socket.emit()`
instead.
You can use socket.broadcast
as mentioned in API doc:
socket.broadcast.to(socketId).emit('msg', 'msg data');