javaandroiddatetime-parsingparseexceptionthreetenbp

org.threeten.bp.format.DateTimeParseException: Text '2018-07-22T14:00:00-03:00' could not be parsed at index 19


    public static String formatter(String dateInPattern, String dateOutPattern) {
    OffsetDateTime dateInPatternFormat = OffsetDateTime.parse(dateInPattern, DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ssZ"));
    Date dateInValue = DateTimeUtils.toDate(Instant.parse(dateInPatternFormat.toString()));
    OffsetDateTime dateOutPatternFormat = OffsetDateTime.parse(dateOutPattern);

    return dateOutPatternFormat.format(DateTimeFormatter.ofPattern(dateInValue.toString()));

}

I need to enter a date in this pattern yyyy-MM-dd'T'HH:mm:ss'Z' this is equals (2018-07-22T14:00:00-03:00). And I need an output in this pattern dd/MM/yyyy

Helpe me please.

I have had many problems with date on android :(


Solution

  • Your code is very confusing, with weird names and you seem to be mixing up pattern strings, e.g. yyyy-MM-dd, with value strings, e.g. 2018-07-22.

    The value string 2018-07-22T14:00:00-03:00 can be parsed into an OffsetDateTime without specifying a DateTimeFormatter, since that is the default format of an OffsetDateTime.

    If you then need to format that as dd/MM/yyyy, then use a DateTimeFormatter.

    Don't know why your method takes 2 parameters.

    Example:

    String input = "2018-07-22T14:00:00-03:00";
    OffsetDateTime offsetDateTime = OffsetDateTime.parse(input);
    String output = offsetDateTime.format(DateTimeFormatter.ofPattern("dd/MM/yyyy"));
    System.out.println(output); // prints: 22/07/2018