I am using the PyCharm IDE. I marked a folder as a resource root and wanted to get a file from its directory and was wondering the appropriate way to do so.
In Java, you can use getClass().getResource("/resourceName.extension")
Is there some way to get a path from a python in said manner?
What I want can be accomplished by this answer.
I used the code as follows:
os.path.join(os.path.dirname(__file__), '../audio/music.wav'