phparraysduplicatesgroupingcounting

How to count the consecutive duplicate values in an array?


I have an array like this:

$arr = array(1, 1, 1, 2, 2, 3, 3, 1, 1, 2, 2, 3);

I found the function array_count_values(), but it will group all of the same values and count the occurrences without respecting breaks in the consecutive sequences.

$result[1] = 5
$result[2] = 4
$result[3] = 3

How can I group each set of consecutive values and count the length of each sequence? Notice there are two sets of sequences for the numbers 1, 2, and 3.

The data that I expect to generate needs to resemble this:

[1] = 3;
[2] = 2;
[3] = 2;
[1] = 2;
[2] = 2;
[3] = 1;

Solution

  • It can be done simply manually:

    $arr = array(1,1,1,2,2,3,3,1,1,2,2,3);
    
    $result = array();
    $prev_value = array('value' => null, 'amount' => null);
    
    foreach ($arr as $val) {
        if ($prev_value['value'] != $val) {
            unset($prev_value);
            $prev_value = array('value' => $val, 'amount' => 0);
            $result[] =& $prev_value;
        }
    
        $prev_value['amount']++;
    }
    
    var_dump($result);