This is the expression I need to simplify:
[{(AB)'*(BC)'} + (A'C)']'
Right now I have my answer as (AB + BC).(A' + C)
I don't think my answer is right but I'm not sure. IF someone could show steps on how to simplify that would be really appreciated, thanks!
((AB)'(BC)' + (A'C)')' = ((AB)'(BC)')'(A'C)'' ; DeMorgan
= ((AB)'' + (BC)'')(A'C) ; DeMorgan + double negation
= (AB + BC)(A'C) ; double negation
= ABA'C + BCA'C ; distribution
= BCA' ; AA'=0