I want to pass two parameters in my url pattern but i am getting error no-reverse match i.e 'projects'.While it works fine with only one parameter.
here is main urls file-
urlpatterns = [
path('admin/', admin.site.urls),
path(r'^materials/(?P<name>(\s+)/',include('materials.urls')),
path(r'^projects/',include('projects.urls')),
]
projects.urls-
urlpatterns = [
path('',views.view_projects,name='view_projects'),
path('(?<projectid>\d+)/',views.project_steps,name='project_steps'),
path('(P<projectid>\d+)/(P<stepid>\d+)/',views.project_steps,
name='project_steps'),
]
views.py-
def view_projects(request):
projects = project.objects.all
return render(request,'projects/project_view.html',
{'projects':projects})
def project_steps(request,projectid,stepno=1):
projects = project.objects.all
stepss = steps.objects.all
return render(request,'projects/project_steps.html',
{'projectid':projectid,'steps':stepss,'projects':projects,
'stepno':stepno})
template-
"{% url 'projects' projectid=project.id stepno=step.step_no %}"
You can do something as below.
Old Way
(r'^view_url/(\d+)/(\d+)$', r'app_name.views.view_function'),
def view_function(request, param1, param2):
"""
:param request:
:param param1:
:param param2:
:return:
"""
return render('/* template path and parameters */')
New Way
(r'^view_url/<int:param1>/<int:param2>$', r'app_name.views.view_function'),
def view_function(request, param1, param2):
"""
:param request:
:param param1:
:param param2:
:return:
"""
return render('/* template path and parameters */')
For more details regex pattern in django 2.0 you can check django documentation link. https://docs.djangoproject.com/en/2.1/topics/http/urls/