When calling QMetaMethod::invoke()
on a method that contains default arguments, the invoke fails.
class MyClass : public QObject
{
Q_OBJECT
public:
Q_INVOKABLE MyClass() : QObject(nullptr){}
public slots:
int MyMethod(int a = 0)
{
return a*2;
}
};
int main(int argc, char *argv[])
{
QCoreApplication a(argc, argv);
MyClass* object = new MyClass();
QMetaObject *metaObject = object->metaObject();
for(int i=metaObject->methodOffset(); i<metaObject->methodCount(); i++)
{
if(metaObject->method(i).name() == "MyMethod")
{
int returnVal;
//returns false
metaObject->method(i).invoke(object,
Qt::DirectConnection,
Q_RETURN_ARG(int, returnVal));
break;
}
}
return a.exec();
}
If I pass an int as the first argument, then it runs fine. Is there any way to retrieve the default values of the arguments for the method so that way I can pass those instead of passing nothing?
I was about to manually store the defaults within the class for each method, but this is an ugly hack.
Thanks for your time.
If you review the generated .moc you see the following:
void MyClass::qt_static_metacall(QObject *_o, QMetaObject::Call _c, int _id, void **_a)
{
if (_c == QMetaObject::InvokeMetaMethod) {
MyClass *_t = static_cast<MyClass *>(_o);
Q_UNUSED(_t)
switch (_id) {
case 0: { int _r = _t->MyMethod((*reinterpret_cast< int(*)>(_a[1])));
if (_a[0]) *reinterpret_cast< int*>(_a[0]) = std::move(_r); } break;
case 1: { int _r = _t->MyMethod();
if (_a[0]) *reinterpret_cast< int*>(_a[0]) = std::move(_r); } break;
default: ;
}
}
}
As you can see there are 2 methods generated and that can be verified by printing the methods with that name:
#include <QCoreApplication>
#include <QMetaMethod>
#include <QDebug>
class MyClass: public QObject
{
Q_OBJECT
public:
using QObject::QObject;
public slots:
int MyMethod(int a = 0){ return a*2;}
};
int main(int argc, char *argv[])
{
QCoreApplication a(argc, argv);
MyClass object;
const QMetaObject *metaObject = object.metaObject();
for(int i=metaObject->methodOffset(); i<metaObject->methodCount(); i++)
{
QMetaMethod method = metaObject->method(i);
if(method.name() == QByteArray("MyMethod"))
qDebug()<<i<<method.name();
};
return 0;
}
#include "main.moc"
Output:
5 "MyMethod"
6 "MyMethod"
So what sets them apart? The number of parameters, so you must add a filter that is the parameterCount()
.
#include <QCoreApplication>
#include <QMetaMethod>
#include <QDebug>
class MyClass: public QObject
{
Q_OBJECT
public:
using QObject::QObject;
public slots:
int MyMethod(int a = 0){ return a*2;}
};
int main(int argc, char *argv[])
{
QCoreApplication a(argc, argv);
MyClass object;
const QMetaObject *metaObject = object.metaObject();
for(int i=metaObject->methodOffset(); i<metaObject->methodCount(); i++)
{
QMetaMethod method = metaObject->method(i);
if(method.name() == QByteArray("MyMethod") && method.parameterCount() == 0)
{
int returnVal;
bool status = method.invoke(&object,
Qt::DirectConnection,
Q_RETURN_ARG(int, returnVal));
Q_ASSERT(status);
qDebug()<<returnVal;
}
};
return 0;
}
#include "main.moc"
Output:
0
On the other hand if you want to avoid this kind of problems you can use QMetaObject::invokeMethod()
that makes that verification:
MyClass object;
int returnVal;
bool status = QMetaObject::invokeMethod(&object,
"MyMethod",
Qt::DirectConnection,
Q_RETURN_ARG(int, returnVal));
Q_ASSERT(status);
qDebug()<<returnVal;