I have this piece of code:
CompletableFuture
.supplyAsync(() -> {
return smsService.sendSMS(number);
}).thenApply(result -> {
LOG.info("SMS sended " + result);
});
but I got a compilation error:
The method
thenApply(Function<? super Boolean,? extends U>)in the typeCompletableFuture<Boolean>is not applicable for the arguments((<no type> result) -> {})
You want to use thenAccept not thenApply
thenApply takes a Function which is of the form
public interface Function<T, R> {
R apply(T t);
}
thenAccept takes a Consumer which is of the form
public interface Consumer<T> {
void accept(T t);
}
The lambda you provided does not have a return value; it is void. Because a generic type parameter cannot be void your lambda cannot be casted as a Function interface. On the other hand, the Consumer has a void return type which the lambda could satisfy.