'For' loop on command line in Z shell ('zsh'): "parse error near `done'"

Why am I getting this error? It seems like good syntax to me.

for f in todo/family/* ; echo "$f" ; done

Output:

zsh: parse error near `done'

This is on the regular command line - not in a file.

Missing do in my command.

As per CharlesDuffy's comment, this is clearly a typo/missing syntax related problem.

What I wrote:  for f in todo/family/* ; echo "$f" ; done
#                                      ^ missing do

Bash expected: for f in todo/family/* ; do echo "$f" ; done

Clearly this error/typo is visible using ShellCheck (another great resource).

How to check Bash-related syntax errors:

1. Go to ShellCheck and paste this in:

#!/bin/sh

for f in todo/family/* ; echo "$f" ; done

You will see the error clearly:

$ shellcheck myscript

Line 3:
for f in todo/family/* ; echo "$f" ; done
^-- SC1073: Couldn't parse this for loop. Fix to allow more checks.
                         ^-- SC1058: Expected 'do'.
                         ^-- SC1072: Expected 'do'. Fix any mentioned problems and try again.

Add do with a space, just before echo and everything checks out:

#!/bin/sh

for f in todo/family/* ; do echo "$f" ; done

into ShellCheck - you can see there is no error. Remove the do and you will see what my problem was.

2. Optionally, you could install the shellcheck command