I have a div with the id of "secondHeader" and I want to replace that entire div with another div with the same id of "secondHeader" but instead of replacing it , it just adds the loaded div inside the first one.
$("#secondHeader").load("/logged-in-content.html #secondHeader");
This is what happens...
<div id="secondHeader"><div id="secondHeader"></div></div>
What I want to happen is the secondHeader div from the ajax load to totally replace the secondHeader in the initial page.
I know it sounds dumb, but here's what I'm trying to accomplish...When a user is not logged in, they see a non-logged in header. I am using ajax to allow the person to log into the site and I want to replace the non-logged in header with the logged in one via ajax.
I have tried everything I know such as...
$("#secondHeader").replaceWith($("#secondHeader").load("/logged-in-content.html #secondHeader"));
...and using .remove() before hand...
Any ideas?
I think the best way is to use get instead of load. In your case you can do like this:
$.get("/logged-in-content.html #secondHeader", function(data) {
$("#secondHeader").replaceWith(data);
});
[Edit: removed a paren]
Update: If /logged-in-content.html has more than just the code you need, you can wrap the returning data in another jQuery object and use .find() to extract the container. Try this:
$("#secondHeader").replaceWith($(data).find("#secondHeader"));