I can do a MariaDB fulltext query which searches for the word beginning like this:
select * from mytable
where match(mycol) against ('+test*' in boolean mode)>0.0;
This finds words like "test", "tester", "testing".
If my search string contains special characters, I can put the search string in quotes:
select * from mytable
where match(mycol) against ('+"test-server"' in boolean mode)>0.0;
This will find all rows which contain the string test-server
.
But it seems I cannot combine both:
select * from mytable
where match(mycol) against ('+"test-serv"*' in boolean mode)>0.0;
This results in an error:
Error: (conn:7) syntax error, unexpected $end, expecting FTS_TERM or FTS_NUMB or '*'
SQLState: 42000
ErrorCode: 1064
Placing the ´*´ in the quoted string will return no results (as expected):
select * from mytable
where match(mycol) against ('+"test-serv*"' in boolean mode)>0.0;
Does anybody know whether this is a limitation of MariaDB? Or a bug?
My MariaDB version is 10.0.31
WHERE MATCH(mycol) AGAINST('+test +serv*' IN BOOLEAN MODE)
AND mycol LIKE '%test_serv%'
The MATCH
will find the desired rows plus some that are not desired. Then the LIKE
will filter out the duds. Since the LIKE
is being applied to only some rows, its slowness is masked.
(Granted, this does not work in all cases. And it requires some manual manipulation.)
d'Artagnan
- Use
WHERE MATCH(mycol) AGAINST("+Arta*" IN BOOLEAN MODE)
AND mycol LIKE '%d\'Artagnan%'
Note that I used the suitable escaping for getting the apostrophe into the LIKE
string.
So, the algorithm for your code goes something like:
FULLTEXT
would.FULLTEXT
and are stuck with a slow LIKE
.*
after the last word (or each word?).AGAINST
with those word(s).AND LIKE '%...%'
with the original phrase, suitably escaped.