In my dataframe a column is made up of lists, for example:
df = pd.DataFrame({'A':[[1,2],[2,4],[3,1]]})
I need to find out the location of list [1,2] in this dataframe. I tried:
df.loc[df['A'] == [1,2]]
and
df.loc[df['A'] == [[1,2]]]
but failed totally. The comparison seems very simple but that just doesn't work. Am I missing something here?
Do not use list
in cell, it creates a lot of problem for pandas
. If you do need an object
column, using tuple
:
df.A.map(tuple).isin([(1,2)])
Out[293]:
0 True
1 False
2 False
Name: A, dtype: bool
#df[df.A.map(tuple).isin([(1,2)])]