This is my code :
from sympy import symbols, Equivalent
from sympy.logic.boolalg import to_cnf as fnc, Implies, to_cnf
from sympy.abc import a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, v, w, x, y, z
def eq(a, b):
return fnc(Equivalent(a, b), True)
inr = str(input('Enter formula: '))
x = ' '
for i in inr:
#print(inr[inr.index(i-2)])
if i == '>':
i = '>>'
x += i
elif i == '=':
print(i)
i = 'Equivalent'
x += i
else:
x += i
print(fnc(x, True))
Instead of input =(a,b)
to call Equivalent function
i want to input (a=b)
. How can I do that?
I have tried to controlling the element before and next of =
and add it to Equivalent
function when you enter (a=b) the output should be (a|~b)&(b|~a)
but it does not work.
i= sympy.Equivalent(symbols((inr[inr.index(i) - 1])), symbols(inr[inr.index(i) + 1]))
So, based on your Sample I/O which was:
IN: so when you enter (a=b) the output should be? – user5173426
OUT: it should be (a | ~b) & (b | ~a) – Yacine Benatia
I made a few changes to your existing code:
from sympy import symbols, Equivalent
from sympy.logic.boolalg import to_cnf as fnc, Implies, to_cnf
from sympy.abc import a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, v, w, x, y, z
def eq(a, b):
return fnc(Equivalent(a, b), True)
inr = str(input('Enter formula: '))
x = ' '
# get the part of the formula/string before =
y = inr.rsplit('=', 1)[0]
# get the part of the formula/string after =
z = inr.rsplit('=', 1)[1]
for i in inr:
if i == '>':
i = '>>'
x += i
elif i == '=':
i = 'Equivalent'
x = i
elif i != ')':
x += y
x += ','
x += z
# print(x)
print(fnc(x, True))
OUTPUT: