c++windowscommand-lineprogram-entry-pointwinmain

Command line arguments parsing is different in Windows XP vs Windows 10

Consider the command line argument: 

D:\work\test.exe -a -p

My C++ application's main() receives the arguments as follows:

  1. Windows 10 

    argc = 3  

argv[0] = "D:\work\test.exe"

argv[1] = "-a" 

argv[2] = "-p"

  2. Windows XP 

    argv = 3    

argv[0] = "test.exe"

argv[1] = "-a"   

argv[2] = "-p"

The argument argv[0] is being parsed differently. My application needs them to be same.
Is there any way to get the entire path in Windows XP as well?
I have tried both main and winmain and the result is the same.

Solution

  • You can determine the full path of the application's .exe file like this:

    WCHAR *path = new WCHAR [32768]; // allow for long path names on Win 10
GetModuleFileNameW (NULL, path, 32768);
...
delete [] path;

    Documentation