I am looking for a way to open an apple watch app from another apple watch app. I have found answers for iOS apps. I am looking for something similar to this answer, but for watchOS instead of iOS.
I have tried to duplicate the iOS answer for watchOS but had no luck. The code I used is:
func openApp() {
let url = URL(string:"App Name")
WKExtension.shared().openSystemURL(url!)
}
I was hoping this would open the app, however, nothing happened when the function was called.
The documentation of the openSystemURL(_:)
method clearly states that the URL supplied to it has to support the tel:
or sms:
scheme and can only be used for starting a phone call or writing messages. It cannot be used to open any other applications, especially not 3rd party ones.
watchOS
doesn't support URL schemes at the moment (as of watchOS 5
), unlike iOS
, so you won't be able to open other apps from your app's WatchKit Extension.