c++floating-pointdecimalsetw

How do I move a decimal point left while maintaining number of digits displayed?


I currently have a function that takes in a vector of structs, including all floats, and should return some values after a simple calculation.

My cout function is simply

void taxPrint(std::vector<TaxPayer> &citizen)
{
    int loops = 0;

    std::cout << "\nTaxes due for this year: \n" << std::endl;

    do
    {
        std::cout << "Tax Payer #" << loops << " : $" << citizen[loops].taxes << std::endl;
        loops++;
}
while (loops + 1 <= SIZE);

and the resulting output in console is

Tax Payer #0 : $450000
Tax Payer #1 : $210000

That said, I want it to be

Tax Payer #0 : $4500.00
Tax Payer #1 : $2100.00

I've been messing around with setw() and setprecision() but I don't exactly understand how they work.


Solution

  • std::setw, actually has nothing to do with value precision, it is for padding string with prefixes like: 001-0123-9124 (Padded with 0)

    Example: std::cout << std::setfill('0') << std::setw(5) << 5 << std::endl; will print 00005

    Here is how to use it using std::fixed and std::setprecision:

    void taxPrint(std::vector<TaxPayer> &citizen)
    {
        int loops = 0;
    
        std::cout << "\nTaxes due for this year: \n" << std::endl;
    
        do
        {
            std::cout << "Tax Payer #" << loops << " : $" << std::setprecision(2) 
                      << std::fixed << citizen[loops].taxes / 100. << std::endl;
            loops++;
        }
        while (loops + 1 <= SIZE);
    } // Don't miss this bracket!
    

    Also, look at this question to know more about specifying a fixed precision to a value...