Python - View bot?

I'm trying to write some code for viewbot.

Code:

import requests
from bs4 import BeautifulSoup
import html5lib
import urllib
import argparse, os, time
import urllib.parse, random

headers = {
    'user-agent':'Mozilla/5.0 (Linux; Android 6.0; Nexus 5 Build/MRA58N) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/71.0.3578.98 Mobile Safari/537.36'
    }
login_data = {
    'login': 'xxx',
    'pass': 'xxx',
    'back_url': '' 
    }

Login on site works correctly.

Lists people:

def getPeopleLinks(page):
    links = []
    for link in soups.find_all('a'):
        url = link.get('href')
        if url:
            if 'profile/' in url:
                links.append(url)
    return links

Working...

And other code:

with requests.Session() as session:
        url = "https://xxxxxx.com/Login/?form_login=1"

        post = session.post(url, data=login_data, headers=headers)
print (post.status_code)
print (post.cookies)
r = session.get("https://xxxxxxx.com/online/GIRL")
print (r.status_code)
print (r.cookies)
soups = BeautifulSoup(r.content, 'html5lib')
x = getPeopleLinks(soups)
print(x)
print("http://www.xxxxx.com"+ x[2])
for link in x: 
        urllib.request.urlopen("http://www.xxxxxxx.com"+link)
print(link)

Login: Works correctly.
List of online users: Works correctly; I get all list of profiles.

I think it's a problem here:

for link in x: 
        urllib.request.urlopen("http://www.xxxxxxx.com"+link)
print(link)

I was logged in on another account by mobile, my profile was on the list, but the bot on the PC did not view my profile.

It is because of the problem in the syntax of the url. Or maybe because of there might be an issue in this particular code, try this:

import urllib.request
for path in paths:
    url = 'http://example.com/view-online-profiles/' + path
    page = urllib.request.urlopen(url)
    print(page.read())

Or you can also follow another way:

import requests
for path in paths:
    url = 'http://example.com/view-online-profiles/' + path
    page = requests.get(url)
    print(page) # Would return response object, can obtain status_code or body