[SOLVED] Printing array contents in the same line in awk

Printing array contents in the same line in awk

I have a script where I need to print the array contents in the same line of the previous print statement. Here array is dynamic in size and I have already one print statement which shows column wise output.

For example: let array having 3 contents (arr[1]=2,arr[2]=4,arr[3]=6), min=100, max=200. I have print statement which is printing column wise result.

gawk '{
  ...
  ...
print "Min:" min "\tMax:" max 
for (itr in arr)
print arr[i] " "

}' script.txt

Expected Output:

Min:100  Max:200  2 4 6

My output:

Min:100 Max:200
2
4
6

Please suugest me an approach, how to append the array contents in previous print result.

Solution

Try using echo it has -n option to skip printing newline at the end.

gawk '{
  ...
  ...
echo -n "Min:" min "\tMax:" max 
for (itr in arr)
echo -n arr[i] " "

}' script.sh

Another Approach

gawk '{
  ...
  ...
printf "Min:" min "\tMax:" max 
for (itr in arr)
printf arr[i] " "

}' script.sh

Please refer echo documentation.