I want to make cross table of a variable with all other variables in the data.frame.
library(tidyverse)
library(janitor)
humans <- starwars %>%
filter(species == "Human")
humans %>%
janitor::tabyl(gender, eye_color)
gender blue blue-gray brown dark hazel yellow
female 3 0 5 0 1 0
male 9 1 12 1 1 2
humans %>%
dplyr::select_if(is.character) %>%
dplyr::select(-name, -gender) %>%
purrr::map(.f = ~janitor::tabyl(dat = humans, gender, .x))
Error: Unknown columns `blond`, `none`, `brown`, `brown, grey`, `brown` and ...
Call `rlang::last_error()` to see a backtrace
tably
takes names as arguments and you passed a vector to it.
If you use imap
you'll have access to the name of the column, that you can convert to a symbol, and as janitor
supports quasi-quotation you can write:
humans %>%
select_if(is.character) %>%
select(-name, -gender) %>%
imap(.f = ~janitor::tabyl(dat = humans, !!sym(.y), gender))
#$`hair_color`
# hair_color female male
# auburn 1 0
# auburn, grey 0 1
# auburn, white 0 1
# black 1 7
# blond 0 3
# brown 6 8
# brown, grey 0 1
# grey 0 1
# none 0 3
# white 1 1
#
# $skin_color
# skin_color female male
# dark 0 4
# fair 3 13
Interestingly tabyl.data.frame
calls an unexported function that works on symbols so by calling it directly we can skip the unquoting and use base R.
cols <- setdiff(names(Filter(is.character,humans)), c("name","gender"))
lapply(cols, function(x) janitor:::tabyl_2way(humans, as.name(x), quote(gender)))
# [[1]]
# hair_color female male
# auburn 1 0
# auburn, grey 0 1
# auburn, white 0 1
# black 1 7
# blond 0 3
# brown 6 8
# brown, grey 0 1
# grey 0 1
# none 0 3
# white 1 1
#
# [[2]]
# skin_color female male
# dark 0 4
To make it work with xtable
@akrun's suggestion works here as well :
humans %>%
select_if(is.character) %>%
select(-name, -gender) %>%
imap(.f = ~tabyl(dat = humans, !!sym(.y), gender) %>% rename_at(1,~"x")) %>%
xtableList
or
cols <- setdiff(names(Filter(is.character,humans)), c("name","gender"))
l <- lapply(cols, function(x) {
res <- janitor:::tabyl_2way(humans, as.name(x), quote(gender))
names(res)[1] <- "x"
res
})
xtableList(l)