pythonnumexpr

Error in python numexp module with 'and' operator

I'm using the numexpr module for python. I'm trying to run the next code snippet:

import numexpr as ne


def main():
    result = ne.evaluate('where((1 > 9) & (where(1 > 9, 9, 1) == 0), 2, 3)')
    print(f'Result: {result}')


if __name__ == "__main__":
    main()

But numexpr throws the following error:

TypeError: unsupported operand type(s) for &: 'bool' and 'ConstantNode'

However, if I extract the conflicting section in a separate expression, it works.

def main():
    intermediate_result = ne.evaluate('where(1 > 9, 9, 1) == 0')
    result = ne.evaluate(f'where((1 > 9) & {intermediate_result}, 2, 3)')
    print(f'Result: {result}')

But the idea is to have a single expression. Does anyone know how I could rewrite this formula to make it work?

Thanks in advance.

Solution

  • & is the bitwise and operator. Why not just use and?