[SOLVED] How do I tokenize a char array input into a char and a string?

How do I tokenize a char array input into a char and a string?

I'm trying to ask the user for an input of say, 3 characters. I want to separate the first character and the last two from each other. So if "A13" is a user input, I want to store 'A' in a separate char and "13" in a separate char[].

//initializations
char seatName[4], seatRowName, seatNumber[3];

printf("\n\nPick a seat (Row Seat) ");
scanf("%s", seatName);
seatRowName=seatName[0];
seatNumber=strchr(seatName, seatRowName);
//I get the "error: incompatible types in assignment" on the above line

Sample output:

Pick a seat (Row Seat): A13
//seatRowName = A, seatNumber=13

Solution

Use below code:

seatRowName=seatName[0];
strcpy(seatNumber, &seatName[1]);  // strncpy if you want to be safe

If you would never change seatName, you can also use const char *seatNumber = &seatName[1];

Why does it work:

             +0  +1  +2  +3
            +---+---+---+---+
   seatName | A | 1 | 3 | \0|
            +---+---+---+---+
             [0] [1] [2] [3]

In memory seatName stores the content in contiguous space. This approach would work fine even for inputs like A3. You should provide other sanity checks to input.

seatNumber=strchr(seatName, seatRowName);
I get the "error: incompatible types in assignment" on the above line

strchr returns char * and type of seatNumber is char [3]. Because types of RHS and LHS are different you are getting above error. Unlike many popular languages C doesn't allow this.

Assigning apples to oranges is almost always incorrect. strcpy(A, B); instead of A = B would work in this case.