I want to get a result like
result
-------------------------------------------------------
id | uuid | user_id |created_date | amount | name
-------------------------------------------------------
1 | ABC | 1 | 2019/5/1 | 5 | xa
2 | PQR | 2 | 2019/5/5 | 150 | xb
A query that I trying to use
SELECT(SELECT SUM(paid_amount) WHERE ID = t1.**HERE**) AS sub1,
(t1.amount - sub1) AS sub2
FROM invoice t1 CROSS JOIN
invoice_paid t2;
Table struct in my DB
table invoice_paid
------------------------------------
id | uuid | paid_date | paid_amount
------------------------------------
1 | ABC | 2019/5/1 | 15
2 | ABC | 2019/5/5 | 80
table invoice
-------------------------------------------------------
id | uuid | user_id |created_date | amount | name
-------------------------------------------------------
1 | ABC | 1 | 2019/5/1 | 100 | xa
2 | PQR | 2 | 2019/5/5 | 150 | xb
I can use sum only 1 condition like where id = 1 but how do I combine this query in select query with a join query. I use beego(golang), MariaDB
You can use this query. It JOINs the invoice table to a derived table of SUMs of all the amounts paid per invoice from invoice_paid, subtracting that total from the invoice amount to get the outstanding amount:
SELECT i.id, i.uuid, i.user_id, i.created_date, i.amount - COALESCE(p.amount, 0) AS amount, i.name
FROM invoice i
LEFT JOIN (SELECT uuid, SUM(paid_amount) AS amount
FROM invoice_paid
GROUP BY uuid) p ON p.uuid = i.uuid
ORDER BY i.id
Output:
id uuid user_id created_date name amount
1 ABC 1 2019-05-01 00:00:00 xa 5
2 PQR 2 2019-05-05 00:00:00 xb 150