I have a big table and want to do partitioning on varchar columns.I have tried to partitioning it using this script in vertical:
create table tb1(
symbol varchar not null,
...
mmid varchar)
PARTITION BY symbol;
I believe that the PARTITION BY did value partitioning on symbol column, and when I load data into the table, it failed with too many partitions as expected.
How can I do range partitioning on symbol column?
For example I know that the DolphinDB could do this by using the below script
sym = `a`abc`aaa`bbc`bac`b`c`cd`cab`abd
val = rand(1.0, 10)
t=table(sym, val)
db=database("/tmp/db", RANGE, `a`b`c`d)
db.createPartitionedTable(t, `table, `sym)
the patitions will be a-b b-c and c-d.
You can use any deterministic function in the PARTITION BY
clause.
For example:
CREATE TABLE tb1 (
symbol varchar NOT NULL
) PARTITION BY LEFT(symbol,2);
INSERT /*+direct*/ INTO tb1 SELECT 'abc';
INSERT /*+direct*/ INTO tb1 SELECT 'bbc';
INSERT /*+direct*/ INTO tb1 SELECT 'bca';
SELECT DISTINCT partition_key
FROM partitions
WHERE projection_name LIKE 'tb1%';
partition_key
---------------
ab
bb
bc