I would like to include all the folders contained in "" within a folder that will be created in the package that will be called "common".
To be more explicite, I would like the tree structure to be in this form:
mypackage.jar
| common
| library
| public
| layout
| application
| rss
| config
| package.properties
| .htaccess
For the moment it works however the deliverable has this form:
mypackage.jar
| library
| public
| layout
| application
| rss
| config
| package.properties
| .htaccess
I can't figure out how to do this operation, which seems rather simple. Sorry, this is the first time I've done maven scripts.
Thank you very much for your time :)
Here is my code :
<build>
<directory>target</directory>
<finalName>${project.artifactId}-${project.version}</finalName>
<outputDirectory>${project.build.directory}/pdc</outputDirectory>
<resources>
<resource>
<directory>${project.basedir}</directory>
<includes>
<include>library/</include>
<include>public/</include>
<include>layout/</include>
<include>application/</include>
<include>rss/</include>
<include>config/include.php</include>
<include>config/constant.php</include>
<include>.htaccess</include>
<include>package.properties</include>
</includes>
</resource>
</resources>
<plugins>
<plugin>
<artifactId>maven-compiler-plugin</artifactId>
<version>2.3.2</version>
</plugin>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>2.4</version>
<configuration>
<outputDirectory>target</outputDirectory>
</configuration>
</plugin>
</plugins>
</build>
Add targetPath
as below.
<project>
<build>
...
<resources>
<resource>
<targetPath>common</targetPath>
...
</resource>
</resources>
<testResources>
...
</testResources>
...
</build>
</project>