Is there a Function in Python to easily create a circular Alphabet, so that the letter after z is a and the letter before a is z?
I tried something with chr() and .join(Alphabet), but that didn't worked because i got the error message an integer is required (got type str).
for character in word:
if chr(Alphabet[Alphabet.find(character)) >= "z":
new_Alphabet = Alphabet.join(Alphabet)
elif chr(Alphabet[Alphabet.find(character)) <= "a":
new_Alphabet = Alphabet.join(Alphabet[:-1])
Use itertools.cycle ans string.ascii_lowercase:
from itertools import cycle
import string
circular_alphabet = cycle(string.ascii_lowercase)
That is an infinite iterator with the lowercase letters:
>>> "".join(next(circular_alphabet ) for _ in range(50))
'abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwx'