javascriptnode.jstypescriptexpressreq

Array.find() method usage with req.param in TypeScript

I am trying to understand basics of "express" package of JS and I am stuck with getting array elements based on index that comes from URL.

Here is my code, this is almost a copy of udemy instructor's code, I was writing simultaneosly.

const express = require('express');
const app = new express();

const users = [
    { id: 1 , name: "harun" },
    { id: 2 , name:"apo" },
    { id: 3 , name: "ogi" }
]


app.get('/', (req,res) => {
    res.send("Welcome to my Page");
});

app.get('/api/users', (req,res) => {
    console.table(users);
    res.send(users);
});

app.get('/api/users/:id', (req,res) => {
    const user = users.find(c => c.id === parseInt(req.param.id));
    if(user === null) res.status(404).send("User is not found");
    res.send(user);
});


const port = process.env.PORT || 3000;
app.listen(port, () => console.log(`Listening on port: ${port}`));

Localhost page reaches status 404, user is not found. Problem is ,most probably, about the line:

 const user = users.find(c => c.id === parseInt(req.param.id));

Can someone help me to fix this?

Solution

  • I think you're looking in the wrong place. Express provides the route params in the req.params not the req.param.

    Maybe changing it to: parseInt(req.params.id, 10) will help you