I want the dry run of the code for the first 3 iterations to understand. THe output of the code is : abcdbcdbcdbcdbc........(infinte times)
I know how for loop works and put char also.I did not dry run as i was not understand will the third argument in the for loop will increment or not.
#include <stdio.h>
int main()
{
for (putchar('a');putchar('b');putchar('d'))
putchar('c');
return 0;
}
putchar always returns the char that you put. So for instance, putchar('a') returns 'a'. With that in mind, let's have a look at how the for loop works:
for ( init_clause ; cond_expression ; iteration_expression ) loop_statement
The init_clause is putchar('a'). This prints a once, because the init_clause is evaluated once at the beginning of the for loop.
The cond_expression is putchar('b'). This is checked every run through the loop, which is why it always prints b. And as it returns 'b' every time, the loop never stops. The loop would only stop if the cond_expression returned 0 or the loop is exited otherwise, for instance through break.
The iteration_expression is putchar('d'), hence d is printed every time. The loop_statement is putchar('c'), printing c.
The result is printing a once, followed by an infinite amount of bcd. The reason why you get them in this order is because in every run throught the loop, it first checks the cond_expression, executes the loop_statement and then the iteration_expression.