Consider a collection with the following documents:
{
"_id" : 1,
"name" : "Class 1",
"students" : [
{ "rollNo" : 10001, "name" : "Ram", "score" : 65 },
{ "rollNo" : 10002, "name" : "Shyam", "score" : 90 }, <=
{ "rollNo" : 10003, "name" : "Mohan", "score" : 75 } <=
]
},
{
"_id" : 2,
"name" : "Class 2",
"students" : [
{ "rollNo" : 20001, "name" : "Krishna", "score" : 88 },
{ "rollNo" : 20002, "name" : "Sohan", "score" : 91 }, <=
{ "rollNo" : 20003, "name" : "Radhika", "score" : 82 },
{ "rollNo" : 20004, "name" : "Komal", "score" : 55 },
{ "rollNo" : 20005, "name" : "Sonam", "score" : 91 } <=
]
},
{
"_id" : 3,
"name" : "Class 3",
"students" : [
{ "rollNo" : 30001, "name" : "Monika", "score" : 77 }, <=
{ "rollNo" : 30002, "name" : "Rahul", "score" : 81 } <=
]
}
My objective is to get top N students from each array ordered by descending score (consider top 2 students order by score).
My expected result is:
If you just want the student records without the grouping you can simply $unwind
and then $sort
:
db.collection.aggregate([
{ $unwind: "$students" },
{ $sort: { "students.score": -1 } },
{ $limit: 2 }
])
That would leave however the students
object. For cleaner output you could use $replaceRoot
with $mergeObjects
:
db.collection.aggregate([
{ $unwind: "$students" },
{ $sort: { "students.score": -1 } },
{ $replaceRoot: {
newRoot: {
$mergeObjects: [ { _id: "$_id", class: "$name" }, "$students" ]
}
}
},
{ $limit: 2 }
])
See it working here
This would give you the following output:
[
{
"_id": 2,
"class": "Class 2",
"name": "Sonam",
"rollNo": 20005,
"score": 91
},
{
"_id": 2,
"class": "Class 2",
"name": "Sohan",
"rollNo": 20002,
"score": 91
}
]
UPDATE:
Use this to get top 2 for each group:
db.collection.aggregate([
{ $unwind: "$students" },
{ $sort: { "students.score": -1 }
},
{
$group: {
"_id": "$_id",
"name": { $first: "$name" },
"students": { $push: "$students" }
}
},
{
"$project": {
"top_two": { "$slice": [ "$students", 2 ] }
}
}
])
See it working here