Using lxml, how can I access/iterate the processing-instructions located before the root open tag or after the root close tag?
I have try this, but, according to the documentation, it only iterates inside the root element:
import io
from lxml import etree
content = """\
<?before1?>
<?before2?>
<root>text</root>
<?after1?>
<?after2?>
"""
source = etree.parse(io.StringIO(content))
print(etree.tostring(source, encoding="unicode"))
# -> <?before1?><?before2?><root>text</root><?after1?><?after2?>
for node in source.iter():
print(type(node))
# -> <class 'lxml.etree._Element'>
My only solution is to wrap the XML with a dummy element:
dummy_content = "<dummy>{}</dummy>".format(etree.tostring(source, encoding="unicode"))
dummy = etree.parse((io.StringIO(dummy_content)))
for node in dummy.iter():
print(type(node))
# -> <class 'lxml.etree._Element'>
# <class 'lxml.etree._ProcessingInstruction'>
# <class 'lxml.etree._ProcessingInstruction'>
# <class 'lxml.etree._Element'>
# <class 'lxml.etree._ProcessingInstruction'>
# <class 'lxml.etree._ProcessingInstruction'>
Is there a better solution?
You can use the getprevious()
and getnext()
methods on the root element.
before2 = source.getroot().getprevious()
before1 = before2.getprevious()
after1 = source.getroot().getnext()
after2 = after1.getnext()
See https://lxml.de/api/lxml.etree._Element-class.html.
Using XPath (on the ElementTree
or Element
instance) is also possible:
before = source.xpath("preceding-sibling::node()") # List of two PIs
after = source.xpath("following-sibling::node()")