I have two files, file A and file B. File A uses a class from file B. My goal is to reference the TypeDoc output for a class used in file B in the TypeDoc output for file A. I can't seem to do this.
I know you can reference a symbol contained in the same file with TypeDoc with double brackets, like [[Foo]]
, but this didn't work for an external type like this.
/** Trying to reference [[FileB.InnerClass]] like this doesn't work. */
// This here is what I want to include
export type InnerClass = FileB.InnerClass;
// More code...
Is this possible to achieve?
yes, it's possible.
import
import { InnerClass } from './FileB';
/**
* See the [[InnerClass]] for more details.
*/
export type innerClass = InnerClass;
when typedef
it's global use this command:
typedoc --out ./docs --target ES6 ./src/
or this when it's local:
npx typedoc --out ./docs --target ES6 ./src/
./docs
is folder where generate documentation.
./src/
is folder where your code is.
--target ES6
version of JavaScript.
If you want to show only classes without different modules, use this flag --mode file
:
npx typedoc --out ./docs --mode file --target ES6 ./src/
for more info, see documentation.